Cho f(x) là hàm số liên tục trên [a;b] (với a<b) và  F(x) là một nguyên hàm của f(x)  trên [a;b] . Mệnh đề nào dưới đây đúng?

Ta có \(% MathType!MTEF!2!1!+-
% feaahqart1ev3aqatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbuLwBLn
% hiov2DGi1BTfMBaeXatLxBI9gBaerbd9wDYLwzYbItLDharqqtubsr
% 4rNCHbGeaGqiVCI8FfYJH8YrFfeuY-Hhbbf9v8qqaqFr0xc9pk0xbb
% a9q8WqFfeaY-biLkVcLq-JHqpepeea0-as0Fb9pgeaYRXxe9vr0-vr
% 0-vqpWqaaeaabiGaciaacaqabeaadaqaaqaaaOqaaabaaaaaaaaape
% Waa8qCa8aabaWdbiaadAgadaqadaWdaeaapeGaamiEaaGaayjkaiaa
% wMcaaiaabsgacaWG4baal8aabaWdbiaadkgaa8aabaWdbiaadggaa0
% Gaey4kIipakiabg2da9iabgkHiTmaadmaapaqaa8qacaWGgbGaaiik
% aiaadkgacaGGPaGaeyOeI0IaamOramaabmaapaqaa8qacaWGHbaaca
% GLOaGaayzkaaaacaGLBbGaayzxaaGaeyO0H4Taamiraaaa!4E95!
\int\limits_b^a {f\left( x \right){\rm{d}}x} = – \left[ {F(b) – F\left( a \right)} \right] \Rightarrow D\) sai.

Diện tích \(% MathType!MTEF!2!1!+-
% feaahqart1ev3aqaMrfvLHfij5gC1rhimfMBNvxyNvgat1dxP5gDCX
% wATLgDZ91EH1Nx7jwF7XfBLzgD8bIzCXwzMrhkGGhiCjxANHgDPacx
% YL2zOrhFCrxz4r3EK1hE9bWexLMBbXgBcf2CPn2qVrwzqf2zLnharu
% avP1wzZbItLDhis9wBH5garmWu51MyVXgaruWqVvNCPvMCG4uz3bqe
% e0evGueE0jxyaibaieYlNi-xH8yiVC0xbbL8F4rqqrFfpeea0xe9Lq
% -Jc9vqaqpepm0xbbG8FasPYRqj0-yi0dXdbba9pGe9xq-JbbG8A8fr
% Fve9Fve9Ff0dmeaabaqaciGacaGaaeqabaWaaeaaeaaakeaaqaaaaa
% aaaaWdbiaadofacqGH9aqpdaWdXbWdaeaapeWaaqWaa8aabaWdbiaa
% dAgadaqadaWdaeaapeGaamiEaaGaayjkaiaawMcaaaGaay5bSlaawI
% a7aiaabsgacaWG4baal8aabaWdbiaadggaa8aabaWdbiaadkgaa0Ga
% ey4kIipaaaa!6599!
S = \int\limits_a^b {\left| {f\left( x \right)} \right|{\rm{d}}x} \)\(% MathType!MTEF!2!1!+-
% feaahqart1ev3aqaMfcvLHfij5gC1rhimfMBNvxyNvgaCjvANHgDHj
% NCVDhidbWexLMBbXgBcf2CPn2qVrwzqf2zLnharuavP1wzZbItLDhi
% s9wBH5garmWu51MyVXgaruWqVvNCPvMCG4uz3bqee0evGueE0jxyai
% baieYlNi-xH8yiVC0xbbL8F4rqqrFfpeea0xe9Lq-Jc9vqaqpepm0x
% bbG8FasPYRqj0-yi0dXdbba9pGe9xq-JbbG8A8frFve9Fve9Ff0dme
% aabaqaciGacaGaaeqabaWaaeaaeaaakeaaqaaaaaaaaaWdbiabgkDi
% Elaadoeaaaa!4522!
\Rightarrow C\)   sai.

\(% MathType!MTEF!2!1!+-
% feaahqart1ev3aqaM1hvLHfij5gC1rhimfMBNvxyNvgaCLMB0XfBP1
% wA0n3x7fwFETNy9TNzCXwzMrhkGidERmdiCjxANHgDPWfDLHhD7rwF
% 41xpCzMCHn2EX03EY0hxSvMz05cigXfBLzgDOaIm4TYmGWLCPDgA0L
% ciCjxANHgD891EH1Nx7jwFamXvP5wqSXMqHnxAJn0BKvguHDwzZbqe
% fqvATv2CG4uz3bIuV1wyUbqedmvETj2BSbqefm0B1jxALjhiov2Dae
% bbnrfifHhDYfgasaacH8YjY-vipgYlh9vqqj-hEeeu0xXdbba9frFj
% 0-OqFfea0dXdd9vqai-hGuQ8kuc9pgc9q8qqaq-dir-f0-yqaiVgFr
% 0xfr-xfr-xb9adbaqaaeGaciGaaiaabeqaamaabaabaaGcbaaeaaaa
% aaaaa8qadaWdXbWdaeaapeGaamOzamaabmaapaqaa8qacaaIYaGaam
% iEaiabgUcaRiaaiodaaiaawIcacaGLPaaacaqGKbGaamiEaaWcpaqa
% a8qacaWGHbaapaqaa8qacaWGIbaaniabgUIiYdGccqGH9aqpdaWcaa
% WdaeaapeGaaGymaaWdaeaapeGaaGOmaaaadaabcaWdaeaapeGaamOr
% amaabmaapaqaa8qacaaIYaGaamiEaiabgUcaRiaaiodaaiaawIcaca
% GLPaaaaiaawIa7a8aadaqhaaWcbaWdbiaadggaa8aabaWdbiaadkga
% aaaaaa!7D95!
\int\limits_a^b {f\left( {2x + 3} \right){\rm{d}}x} = \frac{1}{2}\left. {F\left( {2x + 3} \right)} \right|_a^b\)  nên A sai.

Theo tính chất của tích phân  \(% MathType!MTEF!2!1!+-
% feaahqart1ev3aqaMLhvLHfij5gC1rhimfMBNvxyNvgaCLMB0XfBP1
% wA0n3x7fwFETNy9T3AUygxSvMz0Hci4bcxYL2zOrxkCrxz4r3EK1hE
% 91ZACXwzMr3wGyexSvMz0HciIbcxYL2zOrxkTyexSvMz0HciHbcxYL
% 2zOrxkGWLCPDgA01fatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbuLwB
% Lnhiov2DGi1BTfMBaeXatLxBI9gBaerbd9wDYLwzYbItLDharqqtub
% sr4rNCHbGeaGqiVCI8FfYJH8YrFfeuY-Hhbbf9v8qqaqFr0xc9pk0x
% bba9q8WqFfeaY-biLkVcLq-JHqpepeea0-as0Fb9pgeaYRXxe9vr0-
% vr0-vqpWqaaeaabiGaciaacaqabeaadaqaaqaaaOqaaabaaaaaaaaa
% peWaa8qCa8aabaWdbiaadUgacaGGUaGaamOzamaabmaapaqaa8qaca
% WG4baacaGLOaGaayzkaaGaaeizaiaadIhaaSWdaeaapeGaamyyaaWd
% aeaapeGaamOyaaqdcqGHRiI8aOGaeyypa0Jaam4Aamaadmaapaqaa8
% qacaWGgbWaaeWaa8aabaWdbiaadkgaaiaawIcacaGLPaaacqGHsisl
% caWGgbWaaeWaa8aabaWdbiaadggaaiaawIcacaGLPaaaaiaawUfaca
% GLDbaaaaa!7A03!
\int\limits_a^b {k.f\left( x \right){\rm{d}}x} = k\left[ {F\left( b \right) – F\left( a \right)} \right]\) ; B đúng.