Sách Toán – Học Toán – Đề Thi Toán https://booktoan.com Học toán, Đề thi toán, Sách giáo khoa Toán, trắc nghiệm Toán online Mon, 12 Jun 2023 12:51:17 +0000 vi hourly 1 https://wordpress.org/?v=7.1.2 Tìm các giá trị thực của tham số \(m\) để phương trình \(\log _2^2x – 5{\log _2}x + 2m – 6 = 0\) có hai nghiệm thực \({x_1};\,{x_2}\) thỏa mãn \(\left( {{x_1} + 2} \right)\left( {{x_2} + 2} \right) = 60\). https://booktoan.com/tim-cac-gia-tri-thuc-cua-tham-so-m-de-phuong-trinh-log-_22x-5log-_2x-2m-6-0-co-hai-nghiem-thuc-x_1x_2-thoa-man-left-x_1-2-rightleft-x_2.html https://booktoan.com/tim-cac-gia-tri-thuc-cua-tham-so-m-de-phuong-trinh-log-_22x-5log-_2x-2m-6-0-co-hai-nghiem-thuc-x_1x_2-thoa-man-left-x_1-2-rightleft-x_2.html#respond Sat, 10 Jun 2023 17:00:00 +0000 https://booktoan.com/tim-cac-gia-tri-thuc-cua-tham-so-m-de-phuong-trinh-log-_22x-5log-_2x-2m-6-0-co-hai-nghiem-thuc-x_1x_2-thoa-man-left-x_1-2-rightleft-x_2.html https://booktoan.com/tim-cac-gia-tri-thuc-cua-tham-so-m-de-phuong-trinh-log-_22x-5log-_2x-2m-6-0-co-hai-nghiem-thuc-x_1x_2-thoa-man-left-x_1-2-rightleft-x_2.html/feed 0 Có bao nhiêu giá trị nguyên của tham số \(m \in \left[ {1\,;\,2023} \right]\) để phương trình \(\left( {{4^{x + 1}} – 65 \cdot {2^x} + 16} \right) \cdot \sqrt {{{\log }_3}{x^2} – m} = 0\) có \(2\) nghiệm nguyên. https://booktoan.com/co-bao-nhieu-gia-tri-nguyen-cua-tham-so-m-in-left-12023-right-de-phuong-trinh-left-4x-1-65-cdot-2x-16-right-cdot-sqrt-log-_3x2-m-0.html https://booktoan.com/co-bao-nhieu-gia-tri-nguyen-cua-tham-so-m-in-left-12023-right-de-phuong-trinh-left-4x-1-65-cdot-2x-16-right-cdot-sqrt-log-_3x2-m-0.html#respond Sat, 10 Jun 2023 17:00:00 +0000 https://booktoan.com/co-bao-nhieu-gia-tri-nguyen-cua-tham-so-m-in-left-12023-right-de-phuong-trinh-left-4x-1-65-cdot-2x-16-right-cdot-sqrt-log-_3x2-m-0.html https://booktoan.com/co-bao-nhieu-gia-tri-nguyen-cua-tham-so-m-in-left-12023-right-de-phuong-trinh-left-4x-1-65-cdot-2x-16-right-cdot-sqrt-log-_3x2-m-0.html/feed 0 Tập hợp \(S\) các giá trị nguyên thuộc khoảng \(\left( { – 2023;\;2023} \right)\) của tham số thực \(m\) sao cho phương trình \({\log _2}\left( {x – \sqrt {{x^2} – 4} } \right).{\log _5}\left( {x – \sqrt {{x^2} – 4} } \right) = {\log _m}\left( {x + \sqrt {{x^2} – 4} } \right)\) có nghiệm \(x\) lớn hơn \(3\). Số phần tử của tập hợp \(S\) là https://booktoan.com/tap-hop-s-cac-gia-tri-nguyen-thuoc-khoang-left-20232023-right-cua-tham-so-thuc-m-sao-cho-phuong-trinh-log-_2left-x-sqrt-x2-4-right-log-_5.html https://booktoan.com/tap-hop-s-cac-gia-tri-nguyen-thuoc-khoang-left-20232023-right-cua-tham-so-thuc-m-sao-cho-phuong-trinh-log-_2left-x-sqrt-x2-4-right-log-_5.html#respond Sat, 10 Jun 2023 17:00:00 +0000 https://booktoan.com/tap-hop-s-cac-gia-tri-nguyen-thuoc-khoang-left-20232023-right-cua-tham-so-thuc-m-sao-cho-phuong-trinh-log-_2left-x-sqrt-x2-4-right-log-_5.html https://booktoan.com/tap-hop-s-cac-gia-tri-nguyen-thuoc-khoang-left-20232023-right-cua-tham-so-thuc-m-sao-cho-phuong-trinh-log-_2left-x-sqrt-x2-4-right-log-_5.html/feed 0 Có bao nhiêu số nguyên \(x\) sao cho ứng với mỗi \(x\) có không quá 728 số nguyên \(y\) thỏa mãn \({\log _4}\left( {{x^2} + y} \right) \ge {\log _3}\left( {x + y} \right)\)? https://booktoan.com/co-bao-nhieu-so-nguyen-x-sao-cho-ung-voi-moi-x-co-khong-qua-728-so-nguyen-y-thoa-man-log-_4left-x2-y-right-ge-log-_3left-x-y-right.html https://booktoan.com/co-bao-nhieu-so-nguyen-x-sao-cho-ung-voi-moi-x-co-khong-qua-728-so-nguyen-y-thoa-man-log-_4left-x2-y-right-ge-log-_3left-x-y-right.html#respond Sat, 10 Jun 2023 17:00:00 +0000 https://booktoan.com/co-bao-nhieu-so-nguyen-x-sao-cho-ung-voi-moi-x-co-khong-qua-728-so-nguyen-y-thoa-man-log-_4left-x2-y-right-ge-log-_3left-x-y-right.html https://booktoan.com/co-bao-nhieu-so-nguyen-x-sao-cho-ung-voi-moi-x-co-khong-qua-728-so-nguyen-y-thoa-man-log-_4left-x2-y-right-ge-log-_3left-x-y-right.html/feed 0 Tìm tham số \(m\) để phương trình \({\log _{\sqrt {2023} }}\left( {x – 2} \right) = {\log _{2023}}\left( {mx} \right)\) có nghiệm thực duy nhất. https://booktoan.com/tim-tham-so-m-de-phuong-trinh-log-_sqrt-2023-left-x-2-right-log-_2023left-mx-right-co-nghiem-thuc-duy-nhat.html https://booktoan.com/tim-tham-so-m-de-phuong-trinh-log-_sqrt-2023-left-x-2-right-log-_2023left-mx-right-co-nghiem-thuc-duy-nhat.html#respond Sat, 10 Jun 2023 17:00:00 +0000 https://booktoan.com/tim-tham-so-m-de-phuong-trinh-log-_sqrt-2023-left-x-2-right-log-_2023left-mx-right-co-nghiem-thuc-duy-nhat.html https://booktoan.com/tim-tham-so-m-de-phuong-trinh-log-_sqrt-2023-left-x-2-right-log-_2023left-mx-right-co-nghiem-thuc-duy-nhat.html/feed 0 Có bao nhiêu số nguyên dương \(a\) sao cho ứng với mỗi \(a\) có đúng hai số nguyên \(b\) thỏa mãn \(\left( {\log _5^{}b – 1} \right)\left( {a{{\log }_2}b – 6} \right) < 0\)? https://booktoan.com/co-bao-nhieu-so-nguyen-duong-a-sao-cho-ung-voi-moi-a-co-dung-hai-so-nguyen-b-thoa-man-left-log-_5b-1-rightleft-alog-_2b-6-right-0.html https://booktoan.com/co-bao-nhieu-so-nguyen-duong-a-sao-cho-ung-voi-moi-a-co-dung-hai-so-nguyen-b-thoa-man-left-log-_5b-1-rightleft-alog-_2b-6-right-0.html#respond Sat, 10 Jun 2023 17:00:00 +0000 https://booktoan.com/co-bao-nhieu-so-nguyen-duong-a-sao-cho-ung-voi-moi-a-co-dung-hai-so-nguyen-b-thoa-man-left-log-_5b-1-rightleft-alog-_2b-6-right-0.html https://booktoan.com/co-bao-nhieu-so-nguyen-duong-a-sao-cho-ung-voi-moi-a-co-dung-hai-so-nguyen-b-thoa-man-left-log-_5b-1-rightleft-alog-_2b-6-right-0.html/feed 0 Giá trị thực của tham số \(m\) để phương trình \(\log _2^2x – 4{\log _2}x + m + 1 = 0\left( 1 \right)\) có hai nghiệm phân biệt \({x_1}\), \({x_2}\) thỏa mãn \({\left( {{x_1} – {x_2}} \right)^2} + 3{x_1}{x_2} = 84\) thuộc khoảng nào sau đây https://booktoan.com/gia-tri-thuc-cua-tham-so-m-de-phuong-trinh-log-_22x-4log-_2x-m-1-0left-1-right-co-hai-nghiem-phan-biet-x_1-x_2-thoa-man-left-x_1-x_2.html https://booktoan.com/gia-tri-thuc-cua-tham-so-m-de-phuong-trinh-log-_22x-4log-_2x-m-1-0left-1-right-co-hai-nghiem-phan-biet-x_1-x_2-thoa-man-left-x_1-x_2.html#respond Sat, 10 Jun 2023 17:00:00 +0000 https://booktoan.com/gia-tri-thuc-cua-tham-so-m-de-phuong-trinh-log-_22x-4log-_2x-m-1-0left-1-right-co-hai-nghiem-phan-biet-x_1-x_2-thoa-man-left-x_1-x_2.html https://booktoan.com/gia-tri-thuc-cua-tham-so-m-de-phuong-trinh-log-_22x-4log-_2x-m-1-0left-1-right-co-hai-nghiem-phan-biet-x_1-x_2-thoa-man-left-x_1-x_2.html/feed 0 Có bao nhiêu giá trị nguyên của tham số \(m\) thuộc khoảng \(\left( { – 2023\,;2023} \right)\) để phương trình \({3.6^x} – \left( {7m – 48} \right).\sqrt {{6^x}} + 2{m^2} – 16m = 0\) có hai nghiệm phân biệt \({x_1},{x_2}\) thỏa mãn \({x_1} + {x_2} \ge 2\,\,?\) https://booktoan.com/co-bao-nhieu-gia-tri-nguyen-cua-tham-so-m-thuoc-khoang-left-20232023-right-de-phuong-trinh-3-6x-left-7m-48-right-sqrt-6x-2m2-16m-0-co-ha.html https://booktoan.com/co-bao-nhieu-gia-tri-nguyen-cua-tham-so-m-thuoc-khoang-left-20232023-right-de-phuong-trinh-3-6x-left-7m-48-right-sqrt-6x-2m2-16m-0-co-ha.html#respond Sat, 10 Jun 2023 17:00:00 +0000 https://booktoan.com/co-bao-nhieu-gia-tri-nguyen-cua-tham-so-m-thuoc-khoang-left-20232023-right-de-phuong-trinh-3-6x-left-7m-48-right-sqrt-6x-2m2-16m-0-co-ha.html https://booktoan.com/co-bao-nhieu-gia-tri-nguyen-cua-tham-so-m-thuoc-khoang-left-20232023-right-de-phuong-trinh-3-6x-left-7m-48-right-sqrt-6x-2m2-16m-0-co-ha.html/feed 0 Phương trình \({{\rm{e}}^x} – {{\rm{e}}^{\sqrt {2x + 1} }} = 1 – {x^2} + 2\sqrt {2x + 1} \) có nghiệm thuộc khoảng nào https://booktoan.com/phuong-trinh-rmex-rmesqrt-2x-1-1-x2-2sqrt-2x-1-co-nghiem-thuoc-khoang-nao.html https://booktoan.com/phuong-trinh-rmex-rmesqrt-2x-1-1-x2-2sqrt-2x-1-co-nghiem-thuoc-khoang-nao.html#respond Sat, 10 Jun 2023 17:00:00 +0000 https://booktoan.com/phuong-trinh-rmex-rmesqrt-2x-1-1-x2-2sqrt-2x-1-co-nghiem-thuoc-khoang-nao.html https://booktoan.com/phuong-trinh-rmex-rmesqrt-2x-1-1-x2-2sqrt-2x-1-co-nghiem-thuoc-khoang-nao.html/feed 0 Tìm \(m\) để bất phương trình \({3^x} + {4^x} + {5^x} + {6^x} \ge 4 + mx\) có tập nghiệm là \(\mathbb{R}\). https://booktoan.com/tim-m-de-bat-phuong-trinh-3x-4x-5x-6x-ge-4-mx-co-tap-nghiem-la-mathbbr.html https://booktoan.com/tim-m-de-bat-phuong-trinh-3x-4x-5x-6x-ge-4-mx-co-tap-nghiem-la-mathbbr.html#respond Sat, 10 Jun 2023 17:00:00 +0000 https://booktoan.com/tim-m-de-bat-phuong-trinh-3x-4x-5x-6x-ge-4-mx-co-tap-nghiem-la-mathbbr.html https://booktoan.com/tim-m-de-bat-phuong-trinh-3x-4x-5x-6x-ge-4-mx-co-tap-nghiem-la-mathbbr.html/feed 0