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	<title>Sách Toán &#8211; Học Toán &#8211; Đề Thi Toán</title>
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		<title>Cho tứ diện \(ABCD\), trên các cạnh \(BC,\,\,BD,\,\,AC\) lần lượt lấy các điểm \(M,\,\,N,\,\,P\) sao cho \(BC = 3BM,\,\,BD = \dfrac{3}{2}BN,\,\,AC = 2AP\). Mặt phẳng \(\left( {MNP} \right)\) chia khối tứ diện \(ABCD\) thành 2 phần có thể tích là \({V_1},\,\,{V_2}\)</title>
		<link>https://booktoan.com/cho-tu-dien-abcd-tren-cac-canh-bcbdac-lan-luot-lay-cac-diem-mnp-sao-cho-bc-3bmbd-dfrac32bnac-2ap-mat-phang-left-m.html</link>
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		<dc:creator><![CDATA[admin]]></dc:creator>
		<pubDate>Fri, 27 May 2022 12:15:52 +0000</pubDate>
				<category><![CDATA[Trắc nghiệm Khối đa diện]]></category>
		<category><![CDATA[The tich da dien VDC]]></category>
		<category><![CDATA[VDC Toan 2022]]></category>
		<category><![CDATA[vdc-toan-2022]]></category>
		<guid isPermaLink="false">https://booktoan.com/?p=194816</guid>

					<description><![CDATA[Cho tứ diện \(ABCD\), trên các cạnh \(BC,\,\,BD,\,\,AC\) lần lượt lấy các điểm \(M,\,\,N,\,\,P\) sao cho \(BC = 3BM,\,\,BD = \dfrac{3}{2}BN,\,\,AC = 2AP\). Mặt phẳng \(\left( {MNP} \right)\) chia khối tứ diện \(ABCD\) thành 2 phần có thể tích là \({V_1},\,\,{V_2}\). Tính tỉ số \(\dfrac{{{V_1}}}{{{V_2}}}\) A. \(\dfrac{{{V_1}}}{{{V_2}}} = \dfrac{{26}}{{19}}\) B. \(\dfrac{{{V_1}}}{{{V_2}}} = \dfrac{3}{{19}}\) C. \(\dfrac{{{V_1}}}{{{V_2}}} [&#8230;]]]></description>
		
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		<title>Cho hàm số \(f\left( x \right)\) liên tục trên \(\mathbb{R}\) và thỏa mãn \(f\left( x \right) = f\left( {5 &#8211; x} \right),\forall x \in \mathbb{R}\).Biết \(\int\limits_2^3 {f\left( x \right)} dx = 2\). Tính \(I = \int\limits_2^3 {xf\left( x \right)} dx\).￼</title>
		<link>https://booktoan.com/cho-ham-so-fleft-x-right-lien-tuc-tren-mathbbr-va-thoa-man-fleft-x-right-fleft-5-x-rightforall-x-in-mathbbr-biet-intlimits_23-fleft-x.html</link>
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		<dc:creator><![CDATA[admin]]></dc:creator>
		<pubDate>Fri, 08 Apr 2022 15:37:46 +0000</pubDate>
				<category><![CDATA[Trắc nghiệm Tích phân]]></category>
		<category><![CDATA[tich phan nang cao]]></category>
		<category><![CDATA[vdc-toan-2022]]></category>
		<guid isPermaLink="false">https://booktoan.com/?p=194410</guid>

					<description><![CDATA[Cho hàm số \(f\left( x \right)\) liên tục trên \(\mathbb{R}\) và thỏa mãn \(f\left( x \right) = f\left( {5 &#8211; x} \right),\forall x \in \mathbb{R}\).Biết \(\int\limits_2^3 {f\left( x \right)} dx = 2\). Tính \(I = \int\limits_2^3 {xf\left( x \right)} dx\). A. \(I = 15\).                     B. \(I = 5\).                     C. \(I = 20\).                   [&#8230;]]]></description>
		
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		<title>Cho \(f\left( x \right)\)có \(f\left( 0 \right) = 1\)và \(f\left( {\frac{\pi }{4}} \right) = \frac{\pi }{8}\) và \(f&#8217;\left( x \right) = \frac{{4m}}{\pi } + {\sin ^2}x\) (với \(m\) là tham số ). Tính \(\int\limits_0^\pi  {f\left( x \right)} {\rm{dx}}\) ?</title>
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		<dc:creator><![CDATA[admin]]></dc:creator>
		<pubDate>Fri, 08 Apr 2022 14:46:50 +0000</pubDate>
				<category><![CDATA[Trắc nghiệm Tích phân]]></category>
		<category><![CDATA[tich phan nang cao]]></category>
		<category><![CDATA[vdc-toan-2022]]></category>
		<guid isPermaLink="false">https://booktoan.com/?p=194406</guid>

					<description><![CDATA[Cho \(f\left( x \right)\)có \(f\left( 0 \right) = 1\)và \(f\left( {\frac{\pi }{4}} \right) = \frac{\pi }{8}\) và \(f&#8217;\left( x \right) = \frac{{4m}}{\pi } + {\sin ^2}x\) (với \(m\) là tham số ). Tính \(\int\limits_0^\pi&#160; {f\left( x \right)} {\rm{dx}}\)&#160;? A. \( &#8211; \frac{\pi }{2} + \frac{{{\pi ^2}}}{8}\). &#160;&#160; B. \( &#8211; 3 + \frac{\pi }{2}\). C. [&#8230;]]]></description>
		
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