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	<title>Sách Toán &#8211; Học Toán &#8211; Đề Thi Toán</title>
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		<title>Giải phương trình \(\frac{{6 &#8211; 10\sin \left( {x &#8211; \frac{\pi }{3}} \right) + \cos 2x}}{{\sin 2x}} = \sqrt 3 \).</title>
		<link>https://booktoan.com/giai-phuong-trinh-frac6-10sin-left-x-fracpi-3-right-cos-2xsin-2x-sqrt-3.html</link>
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		<dc:creator><![CDATA[admin]]></dc:creator>
		<pubDate>Sun, 24 Oct 2021 02:29:31 +0000</pubDate>
				<category><![CDATA[Phương trình lượng giác - Tự luận]]></category>
		<category><![CDATA[PTLG HSG]]></category>
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					<description><![CDATA[Giải phương trình \(\frac{{6 &#8211; 10\sin \left( {x &#8211; \frac{\pi }{3}} \right) + \cos 2x}}{{\sin 2x}} = \sqrt 3 \). Lời giải Điều kiện: \(\sin 2x \ne 0 \Leftrightarrow 2x \ne k\pi&#160; \Leftrightarrow x \ne \frac{{k\pi }}{2}\)\(\left( {k \in \mathbb{Z}} \right)\). Khi đó ta có phương trình tương đương: \(6 + 10\sin \left( {\frac{\pi }{3} [&#8230;]]]></description>
		
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		<title>Giải phương trình sau: \(\sin x + \sin y + \sin \left( {x + y} \right) = \frac{{3\sqrt 3 }}{2}\).</title>
		<link>https://booktoan.com/giai-phuong-trinh-sau-sin-x-sin-y-sin-left-x-y-right-frac3sqrt-3-2.html</link>
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		<dc:creator><![CDATA[admin]]></dc:creator>
		<pubDate>Sat, 23 Oct 2021 14:23:51 +0000</pubDate>
				<category><![CDATA[Phương trình lượng giác - Tự luận]]></category>
		<category><![CDATA[On thi Luong Giac]]></category>
		<category><![CDATA[PTLG HSG]]></category>
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					<description><![CDATA[Giải phương trình sau: \(\sin x + \sin y + \sin \left( {x + y} \right) = \frac{{3\sqrt 3 }}{2}\). Lời giải               Cách 1: Phương trình \(\sin x + \sin y + \sin \left( {x + y} \right) = \frac{{3\sqrt 3 }}{2}\,\,\,\left( 1 \right)\). Áp dụng bất đẳng thức Bunhiacốpxki và từ \(\left( 1 [&#8230;]]]></description>
		
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