Sách Toán – Học Toán – Đề Thi Toán https://booktoan.com Học toán, Đề thi toán, Sách giáo khoa Toán, trắc nghiệm Toán online Fri, 20 May 2022 09:01:02 +0000 vi hourly 1 https://wordpress.org/?v=7.1.3 Cho hàm số \(f\left( x \right) > 0\) với mọi \(x \in R\), \(f\left( 0 \right) = 1\) và \(f\left( x \right) = \sqrt {x + 1} f’\left( x \right)\) với mọi \(x \in R\) https://booktoan.com/cho-ham-so-fleft-x-right-0-voi-moi-x-in-r-fleft-0-right-1-va-fleft-x-right-sqrt-x-1-fleft-x-right-voi-moi-x-in-r.html https://booktoan.com/cho-ham-so-fleft-x-right-0-voi-moi-x-in-r-fleft-0-right-1-va-fleft-x-right-sqrt-x-1-fleft-x-right-voi-moi-x-in-r.html#respond Fri, 20 May 2022 09:01:02 +0000 https://booktoan.com/?p=194734 https://booktoan.com/cho-ham-so-fleft-x-right-0-voi-moi-x-in-r-fleft-0-right-1-va-fleft-x-right-sqrt-x-1-fleft-x-right-voi-moi-x-in-r.html/feed 0 Cho hàm số \(f\left( x \right) = {x^{2021}} + 2021x\). Gọi \({m_0}\)là số lớn nhất trong các số nguyên \(m\)thỏa mãn \(f\left( {m – 2020} \right) + f\left( {2021m – {5^8}} \right) \le 0\). Mệnh đề nào sau đây đúng? https://booktoan.com/cho-ham-so-fleft-x-right-x2021-2021x-goi-m_0la-so-lon-nhat-trong-cac-so-nguyen-mthoa-man-fleft-m-2020-right-fleft-2021m-58-right-le-0.html https://booktoan.com/cho-ham-so-fleft-x-right-x2021-2021x-goi-m_0la-so-lon-nhat-trong-cac-so-nguyen-mthoa-man-fleft-m-2020-right-fleft-2021m-58-right-le-0.html#respond Thu, 05 Aug 2021 12:40:26 +0000 https://booktoan.com/?p=186693 https://booktoan.com/cho-ham-so-fleft-x-right-x2021-2021x-goi-m_0la-so-lon-nhat-trong-cac-so-nguyen-mthoa-man-fleft-m-2020-right-fleft-2021m-58-right-le-0.html/feed 0 Cho \(f\left( x \right) = \left\{ \begin{array}{l}4x + 1\,\,\,\,\,\,\,\,\,\,khi\,x \ge 1\\3{x^2} + 2\,\,\,\,\,\,\,\,\,khi\,x < 1\end{array} \right.\). Giả sử \(F\left( x \right)\) là nguyên hàm của \(f\left( x \right)\) trên \(\mathbb{R}\) thỏa mãn \(F\left( 0 \right) = 2\). Giá trị của \(F\left( { – 2} \right) + 3F\left( 4 \right)\) bằng https://booktoan.com/cho-fleft-x-right-left-beginarrayl4x-1khix-ge-13x2-2khix-1endarray-right-gia-su-f.html https://booktoan.com/cho-fleft-x-right-left-beginarrayl4x-1khix-ge-13x2-2khix-1endarray-right-gia-su-f.html#respond Thu, 05 Aug 2021 11:06:52 +0000 https://booktoan.com/?p=186690 https://booktoan.com/cho-fleft-x-right-left-beginarrayl4x-1khix-ge-13x2-2khix-1endarray-right-gia-su-f.html/feed 0 Cho hàm số \(f\left( x \right) = \left\{ \begin{array}{l}4{x^3}{\kern 1pt} + 2x + 1{\kern 1pt} {\kern 1pt} {\kern 1pt} \,\,\,\,\,\,{\rm{khi}}{\kern 1pt} {\kern 1pt} {\kern 1pt} x \ge 0\\4x + 1{\kern 1pt} {\kern 1pt} {\kern 1pt} & \,\,\,\,\,\,\,\,\,{\rm{khi}}{\kern 1pt} {\kern 1pt} x < 0\end{array} \right.\), giả sử \(F\) là nguyên hàm của \(f\) trên \(\mathbb{R}\) thỏa mãn \(F\left( 1 \right) = 2\).Giá trị của \(2F\left( { – 1} \right) + 3F\left( 2 \right)\) bằng. https://booktoan.com/cho-ham-so-fleft-x-right-left-beginarrayl4x3kern-1pt-2x-1kern-1pt-kern-1pt-kern-1pt-rmkhikern-1pt-kern-1pt-kern-1pt-x.html https://booktoan.com/cho-ham-so-fleft-x-right-left-beginarrayl4x3kern-1pt-2x-1kern-1pt-kern-1pt-kern-1pt-rmkhikern-1pt-kern-1pt-kern-1pt-x.html#respond Thu, 05 Aug 2021 02:28:03 +0000 https://booktoan.com/?p=186675 https://booktoan.com/cho-ham-so-fleft-x-right-left-beginarrayl4x3kern-1pt-2x-1kern-1pt-kern-1pt-kern-1pt-rmkhikern-1pt-kern-1pt-kern-1pt-x.html/feed 0 Cho hàm số \(y = f\left( x \right) = \left\{ \begin{array}{l}{x^2} + 3{\rm{ }}khi x \ge 1\\5 – x{\rm{ khi }}x < 1\end{array} \right.\). Giả sử \(F\) là nguyên hàm của \(f\) trên \(\mathbb{R}\) thỏa mãn \(F\left( 3 \right) = 20\). Giá trị của \(F\left( { – 1} \right)\) là https://booktoan.com/cho-ham-so-y-fleft-x-right-left-beginarraylx2-3rm-khi-x-ge-15-xrm-khi-x-1endarray-right-gia-su-f-la-nguyen-ham-cua-f-tren.html https://booktoan.com/cho-ham-so-y-fleft-x-right-left-beginarraylx2-3rm-khi-x-ge-15-xrm-khi-x-1endarray-right-gia-su-f-la-nguyen-ham-cua-f-tren.html#respond Tue, 03 Aug 2021 04:37:16 +0000 https://booktoan.com/?p=186658 https://booktoan.com/cho-ham-so-y-fleft-x-right-left-beginarraylx2-3rm-khi-x-ge-15-xrm-khi-x-1endarray-right-gia-su-f-la-nguyen-ham-cua-f-tren.html/feed 0 Cho hàm số \(f(x) = \left\{ \begin{array}{l}2x + 2021\,\,{\rm{khi}}\,\,x \ge 1\\3{x^2} + 2020\,\,{\rm{khi}}\,\,x < 1\end{array} \right.\). Giả sử \(F\) là một nguyên hàm của \(f\) trên \(\mathbb{R}\) thỏa mãn \(F(0) = 2\). Tính \(4F\left( { – 2} \right) + 5F\left( 2 \right)\). https://booktoan.com/cho-ham-so-fx-left-beginarrayl2x-2021rmkhix-ge-13x2-2020rmkhix-1endarray-right-gia-su-f-la-mot-nguyen-ham-cua.html https://booktoan.com/cho-ham-so-fx-left-beginarrayl2x-2021rmkhix-ge-13x2-2020rmkhix-1endarray-right-gia-su-f-la-mot-nguyen-ham-cua.html#respond Mon, 02 Aug 2021 13:21:23 +0000 https://booktoan.com/?p=186581 https://booktoan.com/cho-ham-so-fx-left-beginarrayl2x-2021rmkhix-ge-13x2-2020rmkhix-1endarray-right-gia-su-f-la-mot-nguyen-ham-cua.html/feed 0 Cho hàm số \(f\left( x \right) \) xác định trên \(\mathbb{R}\backslash \left\{ { – 2;2} \right\} \) thỏa mãn \(f’\left( x \right) = \frac{4}{{{x^2} – 4}} \), \(f\left( 0 \right) = 2 \) và \(f\left( { – 3} \right) + f\left( 3 \right) = 0 \). Tính giá trị biểu thức \(P = 2f\left( { – 1} \right) + f\left( 4 \right) \). https://booktoan.com/cho-ham-so-fleft-x-right-xac-dinh-tren-mathbbrbackslash-left-22-right-thoa-man-fleft-x-right-frac4x2-4-fleft-0-right.html https://booktoan.com/cho-ham-so-fleft-x-right-xac-dinh-tren-mathbbrbackslash-left-22-right-thoa-man-fleft-x-right-frac4x2-4-fleft-0-right.html#respond Sun, 01 Aug 2021 02:51:22 +0000 https://booktoan.com/cho-ham-so-fleft-x-right-xac-dinh-tren-mathbbrbackslash-left-22-right-thoa-man-fleft-x-right-frac4x2-4-fleft-0-right.html https://booktoan.com/cho-ham-so-fleft-x-right-xac-dinh-tren-mathbbrbackslash-left-22-right-thoa-man-fleft-x-right-frac4x2-4-fleft-0-right.html/feed 0