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	Các bình luận về: Đề: Cho hình chóp tứ giác đều S.ABCD. Trên các cạnh SA, SB, SC ta lấy các điểm \({A_1},\,{B_1},\,{C_1}\) sao cho: \(\frac{{S{A_1}}}{{SA}} = \frac{2}{3};\,\frac{{S{B_1}}}{{SB}} = \frac{1}{2};\,\frac{{S{C_1}}}{{SC}} = \frac{1}{3}\). Mặt phẳng \(\left( {{A_1}{B_1}{C_1}} \right)\) cắt SD tại \(D_1\). Tính tỉ số \(\frac{{S{D_1}}}{{SD}}\).	</title>
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