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	Các bình luận về: Đề bài: Chứng minh bất đẳng thức:a)$\frac{x^{2} }{a^{2}}+\frac{y^{2} }{b^{2}}=1 \Rightarrow  \frac{1}{x^{2}}+\frac{1}{y^{2} } \geq  (\frac{1}{a}+\frac{1}{b})^{2}                     b)\sqrt{c}(\sqrt{a-c}+ \sqrt{b-c}) \leq  \sqrt{ab}     $	</title>
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