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	Các bình luận về: Đề bài: Biết \(\int\limits_0^1 {\frac{{3x &#8211; 1}}{{{x^2} + 6x + 9}}} dx = 3\ln \frac{a}{b} &#8211; \frac{5}{6}\) trong đó a, b nguyên dương và \(\frac{a}{b}\) là phân số tối giản. Hãy tính ab.	</title>
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