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	Các bình luận về: Cho tích phân \(I = \int\limits_0^\pi {\frac{{x\sin x}}{{{{\cos }^2}x &#8211; 16}}} dx = a\pi \ln \frac{b}{c},\,\left( {a,b,c \in \mathbb{Q},0 &#060; b &#060; c &#060; 8} \right)\). Giá trị của biểu thức \(40a + 3b &#8211; {c^2}\)là	</title>
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