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	Các bình luận về: Cho khối hộp chữ nhật \(ABCD.A&#8217;B&#8217;C&#8217;D&#8217;\) có \(AD = \sqrt 3 AB = \sqrt 3 a\), góc giữa hai mặt phẳng \(\left( {A&#8217;BD} \right)\) và \(\left( {ABCD} \right)\) bằng \({60^0}\). Thể tích của khối hộp chữ nhật đã cho bằng	</title>
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