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	Các bình luận về: Cho hai số thực \(x,y\)thỏa mãn: \({2^{x &#8211; y}} + {2^{{x^2} &#8211; x}} \le \frac{{{2^{{x^2} &#8211; x + 2}}}}{{{2^{{x^2} + y &#8211; 2x}} + 1}}\). Giá trị lớn nhất của \(x &#8211; y\)là\(M\) khi \(x = m\). Tổng \(M + m\)
A. \(\frac{1}{4}\).	B.\(\frac{1}{2}\).	C.\(\frac{1}{2}\).	D.\(\frac{3}{4}\).	</title>
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