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	Các bình luận về: Cho các số thực \(x \ge 1,y &gt; 0\) thỏa mãn \({\log _{2021}}\left( {2021x + 4042} \right) + x &#8211; 2y &#8211; {2021^{2y}} =  &#8211; 1\). Tìm giá trị nhỏ nhất của biểu thức \(P = {x^2} + x + 1 + {2021^{2y}}\) .
A. \(4\) .	B. \(5\) .	C. \(6\).	D. \(3\) .	</title>
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