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	Các bình luận về: Cho các số thực dương \(x;y\) thỏa mãn: \(x + y \le 15\) và \({\log _2}\frac{{{x^2} + 1}}{{2xy + 1}} + x\left( {x &#8211; 2y} \right) = 0\). Giá trị lớn nhất của biểu thức \(A = \frac{{2{{(x + y)}^4}(y &#8211; 3)}}{{81xy}}\) là:	</title>
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