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	Các bình luận về: Biết tích phân \({\rm{I}} = \int\limits_1^2 {\frac{{\ln {{\left( {2{x^2} + 1} \right)}^x} + 2023x}}{{\ln \left[ {{{\left( {2e{x^2} + e} \right)}^{2{x^2} + 1}}} \right]}}} {\rm{dx = }}\,\,a{\rm{.ln3 + }}\,b{\rm{.ln}}\left( {\frac{{\ln 9e}}{{\ln 3e}}} \right)\) . Với \(a,\,b\, \in \mathbb{Q}\) và \(a,\,b\) là các phân số tối giản. Tính \(P = 8a + 4b\)	</title>
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