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	Các bình luận về: &#160; Biết phương trình \({\log _3}\left( {{3^{2x &#8211; 1}} &#8211; {3^{x &#8211; 1}} + 1} \right) = x\) có hai nghiệm \({x_1};{x_2}\)(với \({x_1} &#060; {x_2}\)). Tính giá trị của biểu thức \(P = \sqrt {{3^{{x_1}}}}&#160; &#8211; \sqrt {{3^{{x_2}}}} \).	</title>
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