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	Các bình luận về: 484. Cho khối hộp đứng \(ABCD.A&#8217;B&#8217;C&#8217;D&#8217;\) có mặt đáy \(\left( {ABCD} \right)\) là hình vuông, cạnh \(a\). Góc hợp bởi \(BD&#8217;\) và mặt bên \((AA&#8217;B&#8217;B)\) bằng \(30^\circ \). Tính thể tích khối hộp.	</title>
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